Circles 02 | Best Problems | Practice Session | Class 10 | NCERT | Udaan

📝Download Lecture Notes From PhysicsWallah App/Website.

------------------------------------------------------------------------------

•Scheduled Syllabus For Udaan ( Class 10 ) released describing which topics will be taught for how many days.

•Duration :- 4 months (Dec 2020 - March 2021)

📣 Free Batch Exclusive on our YouTube Channel : Physics Wallah Foundation - 9 & 10

🔎 Batch Details :

1) Best Faculties across India for different Subject/Topics.

2) Complete & Relevant Syllabus Coverage of Class 10th within 4 Months : December 18,2020 - March 31,2021

3) Monday - Saturday : Scheduled Classes Everyday.

•Physics : Friday (4:00 p.m)

•Chemistry : Monday (4:00 p.m)

•Mathematics : Tues, Thur, Sat (7:00 p.m)

•Biology : Wednesday (6:00 p.m)

•History & Geography : Mon, Fri (5:00 p.m)

•Civics & Economics : Wed, Sat (3:00 p.m)

4) Scheduled Syllabus released describing :-
which topics will be taught for how many days.
Available at PhysicsWallah App

----------------------------------------------------------------------------

OUR SOCIAL MEDIA PROFILES :

[PW-Foundation]

•Scheduled Syllabus For Udaan ( Class 10 ) released describing which topics will be taught for how many days.


•Duration :- 4 months (Dec 2020 - March 2021)

📣 Free Batch Exclusive on our YouTube Channel : Physics Wallah Foundation - 9 & 10

🔎 Batch Details :

1) Best Faculties across India for different Subject/Topics.

2) Complete & Relevant Syllabus Coverage of Class 10th within 4 Months : December 18, 2020 - March 31, 2021

3) Monday - Saturday : Scheduled Classes Everyday.

•Physics : Friday (4:00 p.m)

•Chemistry : Monday (4:00 p.m)

•Mathematics : Tues, Thur, Sat (7:00 p.m)

•Biology : Wednesday (6:00 p.m)

•History & Geography : Mon, Fri (5:00 p.m)

•Civics & Economics : Wed, Sat (3:00 p.m)

4) Scheduled Syllabus released describing :-
which topics will be taught for how many days.



OUR SOCIAL MEDIA PROFILES :

[proinbeingnoob]

9:25 We can also do it another way also
Firstly we know that the tangents to an external point are equal in length
Therefore PR = RQ
This implies /_ RQP = 50°
Therefore /_ PRQ = 80°
.'. We know that the angle between the radius and intersection of 2 tangents are supplementary
/_ POQ + /_ PRQ = 180°
Therefore /_ POQ = 100°, ,

[muditmanigoswami]

10:57 If a quadrilateral circumscribes a circle then the sum of opposite angles are supplementry.

[Harshiitr]

26:00
In triangle AMP and BMP
AP = BP (by theorem){ Two tangents are of equal length when the tangent is drawn from an external point to a circle. }
angle BPM = angle APM (by theorem) result of above theorem
PM = PM (common)
By SAS congruence rule
APM congruent to BPM
So by CPCT;
Angle AMP = Angle PMB

So, Angle AMP + Angle PMB= 180
2×AngleAMP = 180
{Angle AMP = 90}


Sir is it correct??

[uzmaparveen]

Sir In the second last question Can we solve this question by using trigonometry table And sir session was amazing... ..No one can explain it better than Thank you so much sir 😊😊

[aryajsw]

simple way to do the challenger question (i think):
JOIN OC
<OCT=90
<OCA+<ACT=90
<OCA = 42
<OAC =42 (in triangle coa oc=oa as both radii so angles opp to those sides are =)
<TAC=96 (found by angle sum property)
<TAC+<OCA+<OAB=180
<OBA=42 (substituting values of <OCA and <TAC)
OB = OA (both radii)
<OBA=<OAB=42 (angles opp to equal sides are =)
so by angle sum property,
<BOA = 96
is this right?

[deepikasolanki]

Sir, we can also do question 1 as = angle ODC = 40°, then OD & OC are radius so they both are equal means it's an isoceles triangle that is why angle OCD = 40°.
Now, by angle sum property of a triangle we can find angle DOC = 100° as well, then by using linear pair property or The sum of two opposite interior angles is equal to the exterior substended angle of a same triangle we can get the angle COA = 80°.
Thank you for the amazing session.
54:49
Sir, in this question
Given: Radius of bigger circle 13cm & radius of smaller circle is 8cm
We have to find PR so by using angle sum property of a triangle in ∆PRO we can get PR = √105 ... But your answer is different so where I did the mistake?

[sandhyasingh]

Sir in that previous year Qn (2015 wala) there was no need to prove angle 1 = angle 2
Directly amp aur BMP ko congruent kar dete
Ap= bp
Pam=PBM each 60 degree
Aur MP common Nikal jata

[JasmeetSingh-idrw]

Sir In Second Question
We can also use this theorem
Angle subtended by a chord at the centre is double the angle at remaining part of circle

[priyankamalik]

Sanyam sir is a emotion <3 . I will surely ace tmr's exam just because of you 😩

[rajendrakumarrahamatkar]

25:09 sir we can also solve this question by proving APBQ a kite
As the greater diagonal of a kite perpendicularly bisects the shorter diagonal

[kirorilal]

Sir Ncert wala ques tha jisme AC aur AB nikalna tha
Sir usme sidha concept lga tha
Inradius(r)= Area of Triangle÷Semi perimeter of triangle

[animex]

This man has changed my entire life ❤️

[kushagrakatare]

Today's problems were classic I am weak in this chapter I think but most of them were done 👍

[ayushsinghg]

50:37 sir in this question, we can also join OC. So this question can also be solved without Alternate segment theorem..
I think in board exam we should not use this theorem as it is not given in 10th part. CBSE ka koi bharosa nahi🙁

[mrab]

Sir mcq waale mai oc equlas to od aa jayega because wo r hai toh angle doc 100 degree aa jayega aur 100 degree - anlge coa =180 karnge toh jaldi ho jayega 3

[shivi]

We can also do the 1st question in different way
Firstly as we know tangent is perpendicular to the radius
Angle A = 90°
In ∆. ABD using angle sum property angle D = 40°
OD=OC (radii)
Therefore angle D equal to angle C that is 40°( angle opposite to the equal side)
In ∆DOC using angle sum property we find angle DOC equal to 100°
NOW angle DOC+ angle AOC = 180 (STRAIGHT LINE)
HERE'S WE FIND angle COA equal to 80°

[prashantydv]

Session starts at 3:33 hope your time won’t waste, thank me later yr 😍

[gaurijuyal]

The ques were really tricky 💀 but ncert seems easy after doing these questions

[shivansh]

26:00 sir maine radius construction karke kar liya bahut short me ho gaya🙏