Circles 02 | Most Important Problems | Practice Session | Class 9 | NCERT | Sprint

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🗓️ Scheduled Syllabus For Sprint ( Class 9th ) released describing which topics will be taught for how many days.

•Duration:-1 month (Jan 2021 - Feb 2021)

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4) Scheduled Syllabus released describing which topics will be taught for how many days.
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❤️ Padhai Karte Rahe, All The Very Best 👍

[PW-Foundation]

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🗓️ Scheduled Syllabus For Sprint ( Class 9th ) released describing which topics will be taught for how many days.


•Duration:-1 month (Jan 2021 - Feb 2021)

🎉 Free Batch Exclusive on our YouTube Channel : Physics Wallah Foundation - 9 & 10

•Batch Details :

1) Best Faculties across India for different Subject/Topics.

2) Complete & Relevant Syllabus Coverage of Class 9th within 1 Month - Fastrack January 4, 2021- February 15, 2021

3) Monday - Saturday : Scheduled Classes everyday.

•Physics : Tuesday, Saturday
•Chemistry : Wednesday, Friday
•Mathematics : Monday, Wednesday, Friday
•Biology : Wednesday, Thursday, Saturday
•S.ST : Tuesday, Thursday, Saturday, Sunday

4) Scheduled Syllabus released describing which topics will be taught for how many days.



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❤️ Padhai Karte Rahe, All The Very Best 👍

[AryanKumar-cyew]

1:07:21
Question no. 25
Proof:- angleD + angleB = 180° (the sum of opposite angle in a cyclic quad is 180°)

AngleD + AngleA = 180° (Co-int

From equation 1 and 2
AngleD + AngleB = AngleD + AngleA
AngleB = AngleA
Now,
In triangleDAB and triangleCBA
AngleADB = AngleBCA (angle in the same segment are equal)
AB = AB (Common)
AngleA = AngleB (proved)

Therefore, triangleDAB is congruent to triangleCBA
Therefore, AD = BC (C.P.C.T)
AC = BD (C.P.C.T)
Hence Proved

[Harsh-bbxd]

22:14 ½AP( alakh pandey) =MP(mohit punia)

[soumay]

Homework Solution :-

OB=OC=OA=5cm
AB=AC=6cm
PERIMETER OF ∆ OAB =16 cm
SEMI PERIMETER = 8 cm
FINDING AREA OF ∆OAB BY HERON'S FORMULA
A = √ S (S-6)(S-5)(S-5)
= √ 8 (8-6)(8-5)(8-5)
= √ 8 2×3×3
= √ 16×9
= √ 144
A = 12 cm²
Now finding height
a =1/2 ×b×h
12= 1/2 ×5 ×h
24 = 5 h
h= 24/5
h = 4.8
now,
BC = 2h
BC = 2 × 4.8
BC = 9.6

[itsfact]

Words of teacher is more effective than any animation wallah content

[anuverma]

Poonia ji ki maths ki duniya....Sanyam ji ki maccha dene wali sir ki Bhannat class....Bohot acche teachers chune hein maths ke liye👌👌👌Thank you Alakh sir

[ankitthakurankit]

CORRECTION- Q15 => the answer should be 48 sir accidently subtracted 48 instead of 42 see 48:59

[tigerboy]

14:22 Done using heron's formula as OA=Radius=5cm(9.6cm)
1/2×5×h=24 cm²(By heron's formula)
H=4.8cm=CM
4.8×2=9.6

[akhilhema]

14:01
Sir we can also solve this ques by finding the area of triangle OBA by using heron's formula nd then equating the answer with 1/2 ×b(AO)×h(BM)
We'll get h from here and the answer by 2×h

[amitabhanand]

Q.4)
Finding area of triangle OAC using heron's formula and 1/2 base ×height
And let height (MC) Be (n)
Then we find value of MC
And BC=2n
i.e=9.6cm

[noobpeace]

I swear, It's actually a video dedicated on the important questions. Thanks!

[priyakumari]

Q25. proof-AB||DC (given)
and AC is transversal angle ACD =angle CAB
also DB is transversal so angle CDB=angleABD
And angleCAB =angleCDB( angles in a same segment )
therefore angleCAB=angleABD
Now,
in triangle DAB and Triangle CBA
AB=BA(common)
angle ADB=angle BCA(angle in the same segment)
angle CAB=angleABD(proved above)
-:triangle DAB=triangleCBA(AAS congruence condition)
by C.P.C.T AD=BC and AC = BD ( diagonals equal)

[faezashakil]

48:02 110° can be calculated by exterior angle property too.

[ayaanmansuri]

21:36 we can also prove that by the quadrilaterals theorum
if CD||AB
then CD=1/2AB

[iamjack]

At this point 20:23 how CM is || to AB?? And how at 24:16 AM PERPENDICULAR TO AC

[simp]

Sir, you did a small mistake at 20:47, which might confuse others. CM is not parallel to AB rather it is parallel to DN. i hope you got that!

[SanjayKumar-rxlp]

Answer of home work ques
In triangle DAB and CBA
AB=AB (COMMON)
angleADB=angleBCA (Angle in same segment)
angleDAB=angleCBA (as angle D+A =180 ; C+B =180 (cointerior angles)and angle A+C=180 ; D+B=180 (opposite angles of cyclic llgm are supplementary ) from above angle A=B )
Above traingles are congruent by (AAS) hence AD=BC and AC=BD (By CPCT))
HENCE PROVED

[bhupendersingh]

Tomorrow is my maths exam and I am well prepared for them all this goes to MP sir ❤️

[renegade]

20:35, CM || AB is not possible, it is perpendicular to AB

[Altruistmekiwi]

we can prove Q25 by AAS as
BCA=BDA
DBA=CAB
AB=AB, HENCE TRIANGLE dab=cab by CPCT you can prove it