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In the given figure, `angle 1 = angle 2 and (AC)/(BD)=(CB)/(CE)
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In the given figure, `angle 1 = angle 2 and (AC)/(BD)=(CB)/(CE)` prove that `Delta ACB~ Delta DCE`.
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In the given figure, `angle 1 = angle 2 and (AC)/(BD)=(CB)/(CE)
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