In the given figure angle CEF = angle CFE F is the midpoint of DC prove that AB/BD=AE/FD

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Question: In the given figure CEF=CFE F is the midpoint of DC prove that AB/BD=AE/FD.

⭕ALGEBRA ( Marks - 20 )

⭕COORDINATE GEOMETRY ( Marks - 06 )

⭕GEOMETRY--Circle+Triangle ( Marks - 15 )

⭕TRIGONOMETRY-- Introduction of Trigo+Application of Trigo ( Marks - 12 )

⭕MENSURATION--Area related to circle+Surface area and volume ( Marks - 10 )

⭕STATISTICS & PROBABILITY-- ( Marks - 11 )

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in the given figure angle cef = angle cfe

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Easy se aasan wala explanation sir thankyou so much sir ❤❤❤

Ar_ahman_u

Great! I have cleared my doubt 🎉. Thank you❤🌹 so much sir... ❤

OUTLAW_

Tomorrow is my boards exam and this just saved me
Thanks sir 😊

vidhyadere

In 3:22 instead of BPT can we do it by :- As EC=FC AND DF=FC, EC=DF?

aadityamathur

Thanks sir all student will be go above 95% because of sir

badrinathgagare

very easily understood thank you soo much sir!!

varnithavimal

Sir i have doubt, in the first part when u used the bpt theorem shouldn't it be Ad/Bd=An/Ne

utsavarora

Thank you so much sir, ,, for these videos but sir, ,, I want to ask that why you only draw DN parallel ???? Sir pls reply

notes_addaclass

Thank you so much sir very nice explanation aa Gaya samjh very good sir

Islamicmotivation_ayesha

Bahut Badhiya Guru ji Bahut acche se aaya 😅

warriorofsaffron

Thank you sir for answering this question in a easy vey 👌👌

User.

Sir then why we r given that F is the midpoint of DC . If we didnt apply it in the question ! ????

ananya...-vprq

2:05 sir AD/DB haoga na instead of AB/DB

SHD_gamers

2:33 sir this is corollary of bpt not bpt

duvettt

Sir i have a doubt, how is fc and ce equal?

chhawarisushil

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