Laurent Series Harder Example

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Laurent Series Harder Example. I hope this video is helpful.
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Thanks, very helpful! One thing to note is, instead of doing guesswork to derive a needed expression we can just write 1/(z + z^2) = X * 1 / (1 - 1/(z+1)) and find X. It seems faster this way.

sudoLife
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Very nice Video, straight to the points

WA-hqls
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Can this type of questions be asked in engineering exams, i felt difficult by doing it

jinuj
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represent the functionz+1/z-1 by irs laurent series in powers of z for the region |z|>1.Answer bro please

tnboys