Finding Exact Value of Trig Functions in Radian Measure

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Very helpful. Made more sense watching this than a 20 minute demonstration from my teacher

lavid
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Quick and right to the point, thanks!

EdzBoss
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This is less of an explanation and more of a demonstration

arthurlee
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I could never thank you enough for this video.

mx_walkz
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I have two questions I guess. If anyone could help that would be great:
1). You found the hypotenuses by knowing being familiar with the triangles (45-45-90 and 30-60-90), right? So does that mean this method only works if the angle creates one of those two triangles?
2). For the first two problems, at least, you drew the triangle in a way that would suggest that the hypotenuse is equivalent to the radius. However, you got different hypotenuses depending on the angle problem, so how can that be if we're assuming that both triangles are formed as part of the same unit circle?

ellieberg
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I don't get how you just knew that the opposite side was sqrt(3) and the hypotenuse was 2...

connorbunch
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thank you dude my teacher wasnt here today and assigned homework anyways so thank you for helping me understand

Gagemcninja