A2 U4.02

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Ignacio M Period 1
Given the time (5 years) we plug that into the equation t=a^(3/2) and it takes 5 2/3 astronomical units.
16x^2 = 4

ignaciomolina
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Michael. P. 4
For the Astronomical Units I got 2.924 because I assumed that we used the general rule of t^2/a^3=1. Therefore, I inputted 5^2 for t and solved. However, I was questioning whether my method was correct or not. And for the last problem, I got 4x.

Michael.Pineda
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Sergio B. Period 1
For the first question I got was 7 because I had multiplied the distance due to the fact of the average of 5 years.
However, for the second question, I had got 4x.
My question is that for the square root of a•b, what do the nth power have to do with the a•b?

sergiojr
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Brian.F Per.4
The farthest the planet would be from the sun is 25.15 astronomical units, I plugged in a and used the equation a=t^(2/3) to solve. The square root of 16x^2 is 4x.

brianflores
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Brian D. Period 1
For the first question I got 7 because I multiplied the distance of Neptune by the 5 years it would take it.
For the second question I got 2√8x.
My question is for the rule of x^a×x^b=a+b. Does this rule only apply for a problem that has a equal x number?

briandelgadillo
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Raul Lopez
Pr. 2
My question is for the last problem, I was wondering if a variable isn't a like term how can we divide that? Like when we divided' x^2/x = x

My answer to the square root of 16x^2 is 4X.

raullopez
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Roberto M. period 4
When you multiply the fractions where would the remander fall into if you have one? & √16X^2= 4X & for the astronomical units away I got 2.92

robertomiranda
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Hector.C.Period 4
So 16^2(1/2) is 4
For the distance I rounded and got 2
My question is, is there a more accurate way of finding the right two multiples? For example the 150 in the video we found 25 and 6. How come I need to accurately find those two?

hectorcabrales
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LaRue
I plugged in the square roots of 125 of 5 and wanted to know if it mattered if the decimal approximation was different

jacoblarue
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Christian Cervantes
Why wont we try using the reciprocal for some of the fractions?
I got 2.92 for the last problem

christiancervantes
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How do you simplify an expression if there is a number over the radical

anthonylittle
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Angel Carrillo Per. 4
2.5^(2/3)=1.84202,  1.844202^(2/3)=1.503854, is what I got for D, I figured the farthest distance would be half of the 5 years.  
Last question: believe that 16x^2^(1/2) simplified is equal to 4x 
how do we simplify an unknown variable raised to a power? 

Ace-qlyc
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Cesar I 1
Answer I got was 4.
My question is 5*5 the same as 5 to the square root of 5

cesarinzunza
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David Ayala P.4
it would 2.924 astronomical units away. I plugged in 5^2 for t and solved from there.
For the final problem i got 4x.
Question:  When solving for the last problem, do you need to do sqrt of 16^(1/2) or is sqrt of 16 good enough?

zxxBubBlZxxz
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Brandon.BV.Period 2

My question is for problems c & d, how exactly would I make an equation that could calculate the distance with the average distance ?

bv
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Michael Romero P4
My question is that I plugged in square root of 125 and 5 and found out that the Decimal approximation is different. Does that matter?
1. I plugged in 5 for the equation of time  and I got 2.924
2. For square roots for 16x^2 I got 4 the square root of x^2

michaelromero
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Shelby p. 4
I believe that 16x^2^(1/2) simplified is equal to 4x
And the furthest distant is 2.924 space units I believe is the unit. And my QUESTION would be: if a square is being square rooted, don't they just cancel out?

smartyoff
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isaiah taylor per 2
 when figuring out how to get the furthest distance will it ever be possible to use the same formula used in  a quadratic formula ??

isaiahtaylor
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Timmothy Roberts per 1

√16×^2 you have to take the square root of 16 and then multiply 4*4 ehat do you do with the 2

timmothyroberts
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Tamir Martin per 2
I understand how to separate all the square roots but I do not understand how to simply or which rule to use

tamirmartin