Find the remainder when 3²⁰²² is divided by 5 | jee mains 2022 solution | jee mains 2022 Maths

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Find the remainder when 3²⁰²² is divided by 5 | jee mains 2022 solution | jee mains 2022 Maths
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3^1=3, last digit 3
3^1=9, last digit 9
3^3=27, last digit 7
3^4=81, last digit 1
3^5=243, last digit 3
3^6=729, last digit 9


3^2020=..., last digit 1
3^2021=..., last digit 3
3^2022=..., last digit 9
9 divide by 5 remains 4...
So, answer is 4

mdpabel
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9/5= -1
(-1)^1011 = -1
-1+5= 4
UNACADEMY ATOMS, NV SIR SHORT TRICK FOR REMAINDER QUESTIONS
SOURCE; BINOMIAL THEOREM ONESHOT BOUNCE BACK SERIES

udddiptasaikia
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Way too complicated. 3^4=81. 81^x always ends in 1, 3^2*(3^4)^505 reduces to in 9*1 modulus 5 is 4. You can also see this in the modulus(3^x, 5) sequence which cycles 3->4->2->1->3...

Kreistor
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Sir 50 se divided krna tha 5 se nhi : Question was find reminder in divided by 50

sachinchouhan