IIT JEE Problems in One Minute | Finding Remainder | Binomial Expansion🔥 #jeemath #umeedjee #jeepyq

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In this video Saurabh Sir will be discussing JEE Previous Year Questions.

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[NoobPerson-xpnn]

Simple
So
3² = 4 ( mod 5 )
3²= -1 ( mod 5 )
(3²)¹⁰¹¹ = -1¹⁰¹¹ ( mod 5 )
So -1 is remainder which is 4
Ans is 4

[shaaniitp]

Jaldi jaldi JEE main 2022 ko iit 2022 likh deta hu cool lagunga 🙂

[nileshparmar]

Sir ase hi short par chhote chhote concept par video bana diya karo plz
Revision hota rahega

[dontmesswthme]

Fermat little theorem bhi use kar sakte he 3²⁰²⁰ ka remainder 1 toh 9* 3²⁰²⁰ ka 4

[Saddestkiddo_irl]

Divide 22 by 4 remainder 2, 3 to the power 2 is 9 divide 9 by 5 remainder is 4 easily takes only 5 8 seconds if u know divisibility

[Your_gamer_bhai]

3^2022
9^1011
(10-1)^1011
-1^1011
-1
But according to mod -1 is the remainder but according to option😂 so -1+5=4

[Suraj-cvor]

Can we use negative remember theorem 🧐🧐🧐

[Saddestkiddo_irl]

U can slove this easily by 3 rule divisibility

[abhayverma]

Sir ye question to 15 sec mein hojayega congruence modulo se aur wo method bhi aasan hai

[madhurim]

IOQM students left the chat. Congruence modulo se 30 seconds mei answer aajayega

[FF-JOD-GAMER]

Totient method take 10 sec to solve these type of questions....

[dred]

Iska simple method batata hu 5^2022 ka one place 9 ayega and 9/5 remainder is 4 sone

[wanisboard]

Rem of 3^2022 ÷ 5 = Rem of 2^2022 ÷ 5.
Now rem of 2022÷ 4= 2
So rem of 2^2022 ÷ 5 = rem of 2^2 ÷ 5 = rem of 4/5 = 4 ans

[neelamkumari-umnv]

Timing 21:53 par sheshfal 5 kese hua sir??

[HarshChaudhary]

Sir ek Kam kro 3^2022 h na toh uski power ki last ki dono digit ko add krdo or option me dekho match krra h kya agr krra h toh pass
Apse jaldi krdiya aadhi fees bhi dena ab sir imandaari se😊

[India-love-]

Sir UPSC csat ki bhi series ab aap leaao 😊plz sir 🙏🏾

[musicmania]

bhai 4 se divide kar diya karo power ko 😂😂 itne jhanjhat ki jarurat nahi

[thisizdevil]

I'm in class 9 and I solved it in 50 seconds

[kangnashorts]

Simple the is also solve by fermet theorem in 10th I solve this in 30 sec😂

[ajaysoni]

Isse achcha fermat little theorem use ker lete sir🥱