Two particles move along an \( x \) axis. The position of particle 1 is given by \( x=6.00 t^{2}...

Two particles move along an \( x \) axis. The position of particle 1 is given by \( x=6.00 t^{2}+3.00 t+2.00 \) (in meters and seconds); the acceleration of particle 2 is given by \( a=-8.00 t \) (in meters per second squared and seconds) and, at \( t=0 \), its velocity is \( 15 \mathrm{~m} / \mathrm{s} \). When the velocities of the particles match, what is their velocity?