Math Olympiad Lecture 6: Surds

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Math Olympiad Lecture 6: This lecture covers the topic of surds including: (i) Laws of Surds; (ii) Conjugate Surds and (iii) Surd within surds.

Links about the Phonetic Peg System

Solutions to the extension problems can be found in the link below:
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I didn’t really pay attention to the video, but all I did was let s=(expression in problem 2) then I squared both sides then you can merge to surd terms[(17+12v2)(17-12v2)] which is the difference of 2 squares, and it equals 1 plus some other stuff then it’s 36=s^2 —> s=6

Hovione
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Hey man thanks for the Lectures I was wondering if you could do a video solving the extension problems because sometimes it's hard to understand how they got to the answer anyways, Thanks dude

John
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thanks, comparison was really useful, never realized it can be used in that context.

finchdoge
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I dont really understand the comparison part, how to assume and compare both side like that. Can give more detail about that? 😅😅😅

benthen
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A think it is easier to let x= sqrt(17+12sqrt(2)) + sqrt(17-12sqrt(2)) then x^2=36 (using binomial squared and difference of squares) then x=6 an discard x=-6 because both terms in x are greater than 0.

martincaputo
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4:07
If we don't rearrange surds from √99+√100 to √100+√99 wouldn't the answer become -9? Because of the conjugate surd √99-√100

ramunasstulga