JEE Advanced Symposium| ISI | CMI | Ellipse | Selected 35 solved examples (Playlist videos)

JEE Advanced Symposium| ISI | CMI | Ellipse | Selected 35 solved examples (Playlist videos) #JeeAdvanced #Mathsmerizing # JeeMains

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[Mathsmerizing]

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[ranadip]

Not one of the but the best channel for jee advanced mathematics 🙏

[boomlight]

It's unbelievable
This video has been uploaded in 2021 and one of the questions at 15:49 has exactly appeared in the 2022 advanced paper without any change, not even a grammatical change . 😮

[AditiSingh-sllx]

Sir at 8:20 there is also a straight method that after squaring Ps1 and Ps2
(Ps1)²+(ps2)² =(s1s2)² which can further written as (2ae)²
and 2(Ps1)(Ps2) =4 ×area

[gyandeepkatiyar]

Sir will you upload all chapters till advance please tell sir?🙏

[onlystudyjee]

Came again to thankyou after watching I went to solve jee advanced questions and tried 3 questions from (2016, 2009, 2022) and solve all of them very easily 😊

[lakshyasharma]

Disclaimer- This channel can make u fall IN LOVE WITH MATHS

[lucky-govp]

Matrices and determinants pls
Appreciate ur efforts

[spandanchakrabarty]

Thanks sir love your videos and your teaching. ♥️♥️

[akshita]

This channel is the best. Thanks a lot sir, and it really inspires us learn more, and practice more, when all these videos boost of confidence at the same time, clear out every concepts. The standard is so good. Thanks a lot sir. Respect 🙏🙏

[sorrymyenglishbad]

Sir, if I do all the questions properly, am I apt for the Advanced examination?

[rajnitripathi]

0:22(radius of incircle), 3:52
8:01
12:09
18:24
22:04

[Rishabh-seyo]

Matrices and sot pls sir and thanku so much

[abhi_journey]

Revision:-8:00, 12:30, 15:49, 32:30, 42:48, 1:10:47, 1:53:00, 2:11:30.

[grandson_f_phixis]

Not a workshop, a supermarket for JEE ADV 😂

[prabalbaishya]

Sir for the 2nd question, I proceeded by taking any general ellipse and the point where the circle is tangent to be acosθ, bsinθ, since this point is common to both ellipse and circle. Now the normal to the circle at this point passes through (ae, 0) so the slope of normal is bsinθ/a(cosθ-e). Also finding the slope of tangent at the point of tangency we get the slope as -b/a*cotθ. Since these two slopes are at 90° so their product must be -1. On putting the values and simplyfying we get cosθ=1/e. But this is not possible as 1/e>1. Sir can you tell me where is the mistake?

[onlystudyjee]

Now, no matters what but I will score full in test from ellipse and parabola part

[onlystudyjee]

26:30


1:36:40
1:40:45
1:51:10
2:05:00
2:19:00
2:29:00

[ssgroast]

2:26:02 chef kiss method of solving that question

[wildnest]

sir can you explain in short, that when we should use which equation for tangent? i find it confusing of when to use parametric and when T=0