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Hybridization of NH3 (ammonia)
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NH3 has three single bonds to H's, and one lone pair.
NONE of that means there are pi bonds, and therefore there are no unhybridized p orbitals necessary.
Therefore, the hybridization is sp3.
NONE of that means there are pi bonds, and therefore there are no unhybridized p orbitals necessary.
Therefore, the hybridization is sp3.
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