How to Derive⚡Sin2A, Cos2A, SIn3A & Cos3A,⚡Trigonometry

Trigonometry, Derivation of Sin2A, Cos2A, SIn3A & Cos3A.
From this tutorial, you will learn how to derive
⚡Sin2A = 2SinACosA (read, 2sinACosA)
⚡Cos2A = (CosA)^2 - (SInA)^2 (read, cos square A minus sin square A)
⚡Cos2A = 2(CosA)^2 - 1 (read, 2cos square A minus 1)
⚡Cos2A = 1 - 2(SinA)^2 (read, 1 minus 2sin square A)
⚡Sin3A = 3SinA - 4(SInA)^3 (read, 3sinA minus 4sin cube A)
⚡Cos3A = 4(CosA)^3 - 3CosA (read, 4cos cube A minus 3 cos A)

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#trigonometry #amplitude #period #Edxcammath4u
#trigonometry #amplitude #period #Edxcammath4u

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