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COS 2A = COS^2 A - SIN^2 A = 1- 2 SIN^2 A = 2COS^2 A -1 = (1 - TAN^2 A) / (1+TAN^2 A) | TRIGONOMETRY
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NCERT CLASS 11 MATHS solutions
NCERT CLASS 12 MATHS solutions
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CLASS 11
SETS :
RELATIONS AND FUNCTIONS :
TRIGONOMETRY :
PRINCIPAL OF MATHEMATICAL INDUCTION :
COMPLEX NUMBERS
LINEAR INEQUALITIES
PERMUTATIONS AND COMBINATIONS :
BINOMIAL THEOREM
SEQUENCE AND SERIES
STRAIGHT LINES
CONIC SECTION
3D GEOMETRY
LIMITS AND DERIVATIVES
MATHEMATICAL REASONING
STATISTICS
PROBABILITY
CLASS 12
RELATIONS AND FUNCTIONS
INVERSE TRIGONOMETRIC FUNCTIONS
MATRICES
DETERMINANTS
CONTINUITY AND DIFFERENTIABILITY
APPLICATIONS OF DERIVATIVES
INTEGRATION
APPLICATIONS OF INTEGRATION
DIFFERENTIAL EQUATIONS
VECTOR ALGEBRA
THREE DIMENSIONAL GEOMETRY
LINEAR PROGRAMMING
PROBABILITY
NCERT CLASS 12 MATHS solutions
BR MATHS CLASS has its own app now.
SUBSCRIBE TO MY CHANNEL TO GET MORE UPDATES
CLASS 11
SETS :
RELATIONS AND FUNCTIONS :
TRIGONOMETRY :
PRINCIPAL OF MATHEMATICAL INDUCTION :
COMPLEX NUMBERS
LINEAR INEQUALITIES
PERMUTATIONS AND COMBINATIONS :
BINOMIAL THEOREM
SEQUENCE AND SERIES
STRAIGHT LINES
CONIC SECTION
3D GEOMETRY
LIMITS AND DERIVATIVES
MATHEMATICAL REASONING
STATISTICS
PROBABILITY
CLASS 12
RELATIONS AND FUNCTIONS
INVERSE TRIGONOMETRIC FUNCTIONS
MATRICES
DETERMINANTS
CONTINUITY AND DIFFERENTIABILITY
APPLICATIONS OF DERIVATIVES
INTEGRATION
APPLICATIONS OF INTEGRATION
DIFFERENTIAL EQUATIONS
VECTOR ALGEBRA
THREE DIMENSIONAL GEOMETRY
LINEAR PROGRAMMING
PROBABILITY
Prove Cos2A=Cos^2A-Sin^2A
COS 2A = COS^2 A - SIN^2 A = 1- 2 SIN^2 A = 2COS^2 A -1 = (1 - TAN^2 A) / (1+TAN^2 A) | TRIGONOMETRY
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#COS(A+B).COS(A-B)=COS²A-SIN²B (or)COS²B-SIN²A
If A, B, C are angles in a triangle, then cos 2A + cos 2B + cos 2C = -1 – 4 cos A cos B cos C
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