How to Prove that the Intersection of Subspaces of a Vector Space is a Subspace

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How to Prove that the Intersection of Subspaces of a Vector Space is a Subspace
  1. The Math Sorcerer
  2. subspace
  3. vector spaces
  4. intersection of subspaces
  5. proof
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Комментарии
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had this exact problem on my lin alg hw and you miraculously had a vid on it thanks!!

raichuk
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Thank you so much for the upload! Didn't know how to approach it myself so this video really cleared things up. Thanks again!

ひまり-pn
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It is always pleasure to me to find your math video. It is really enjoyable to visit every time in "Math Sorcerer".

sayanjitb
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I kinda don't get it? The proof seems kinda circular. It's like "Take any x, y in the intersection of U and W. This means that x, y must be in U and W. Because x, y is in U and W, and U and W are closed under addition, this implies that the intersection of U and W is closed under addition."

Isn't this circular logic? The proof rests on the assumption that an x, y exists in U and W, but what if subspace U and subspace W only have the element {0}. Then, two unique vectors x, y cannot exist.

hello-lbvf
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Thank you soo much.. I understand it easily after your video. Thanks a lot.

ryk
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thanks alot dude. your lessons are very easy to understand. i might just get a good result for this assignment. lol

sifisokhoza
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what happens if there are no vectors that live in the intersection except for the zero vector? is there a way to guarantee that there will be vectors different than the 0 vector?

tomascordova
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I missed a lecture due to covid, I catch up by your video, thank you

Masturbatin
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Sir please send complete exercise of 1.C of this 1st chepter of linear algebra done right.

sajidghaffar
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Sir send Solution of exercise 1.C question

sajidghaffar