Prove that seca-1/seca+1 =[sina / 1+cosa]^2

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Prove that seca-1/seca+1 =[sina / 1+cosa]^2

seca-tana/seca+tana=cos2a/(1+sina)2

seca-1/seca+1=1-cosa/1+cosa

seca-tana2/(1-sina)/(1-sina)

1-cosa/1+cosa=(cota-coseca)^2
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