Mechanics of Materials: Lesson 30 - Shear Moment Diagram, Equation Method...Challenging!

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Your teaching style is amazing. In the statics books I have read, they love to overcomplicate these things, when in reality it can be very clear and intuitive if someone explains it in such good way.

ZeonLP
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Hands up for you sir. In this pandemic we need a professor like you, 👋

bobosamathcee
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I love you man. You just cleared my conceptions about shear force and bending moment diagrams. May God give you good health and all the happiness you desire. Loved your videos, Thank you so much.

nabilabsar
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for those who dose understand why y=9-2x.I think the best way to understand is that the x is negative in x-yplan. but we need a positive distance to compute the total force in rectangle.

study
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Wonderful solids lessons!! really taking the time to explain the problems along with a good sense of humor :))

manuboker
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you are the best professor i ever had .god bless you

busybee
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Your videos are great Jeff! Thank you for posting. This one was tough, hopefully The exam probs aren't this hard. I could not wrap my head around the equation y=9-2x

alishad
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Thanks Jeff!!! Your lessons that make me recall exactly when I was in Civil class sometime in 25 years ago. Appreciated Sir.

vansinhnguyen
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Great Explaination! This actually makes so much sense now:) Thank you!

AdventuringtheWild
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🤣 Im just here for 7:35...
'and THEN what? BAM!'.... it just keeps getting better🤪🤓👍
Thanks for always clarifying my midnight Strengths HW insanity.... with smiles worth replaying.

lightlove
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Thanks For Ur great effort Dr.Jeff, But I think it's quite enough to Find the moment and derive the equation to get the shear force directly or integrate the shear force to find the moment.

ksa
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Thank you I’ve been looking for a solution for this kind of load for ages

gavinyu
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Awesome presentation. I like your humor. 😚

DazzSpace
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thank you for the lesson..the video helped me sooo much for my final exam

HandNoteLala
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Can you add this video to your statics playlist also? I didn't know about this video and had to deal with more advanced problems like this in statics. is there a video with these diagrams but with back to back triangles (both max heights at the center) on a cantilevered beam? im having trouble once i get to the second triangle.

ericescobar
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Can you please explain from where you got y=6/3(x)+9
I did not understand that one

ramaiskandarani
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Very clear explanation, thanks for this. Can we make a formula for the whole beam or only for the part we cut? I noticed in this example that when you try to enter a value of 6 for x you get weird numbers which don't add up. I am in particular curious about this because this problem has a linear load that stops in the middle and thus these are two different loads. I can imagine when the load continued to the end 1 equation is easier.

MeesBorg
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I have a question: At 7:35, wouldn't the shear graph drop straight down 3 kN before becoming parabolic?

johngentry
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my question is why did you sir have to put a negative for x @ 14:11

solomonmule
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Why i sub x=6 in the moment eq i get -4.5 not zero?

eykaaaa