Persistent Bugger Find Multiplicative Persistence JavaScript Codewars Solution

In this Kata, we are tasked with calculating the multiplicative persistence of a number. This means we need to repeatedly multiply the digits of the number until only a single digit remains, and we must count how many steps this takes.

For example, with the number 39, we multiply three times:
- 3 times 9 equals 27,
- 2 times 7 equals 14,
- and 1 times 4 equals 4.

So the persistence of 39 is 3.

In the code, we use a while loop to continuously multiply the digits until we reach a single-digit result, counting each multiplication step.

Explanation:
.toString().split(''): Converts the number into a string and splits it into an array of individual characters (digits).
.map(Number): Converts each string digit back into a number.
.reduce((a, b) =) a * b): Multiplies all the digits together using the reduce method.
while (num less than 10): Continues as long as the number has more than one digit.
count++: Counts the number of multiplication steps.
Finally, the function returns the number of steps it took to reach a single digit.

Hashtags:
#JavaScript #Codewars #MultiplicativePersistence #ProblemSolving #CodingChallenges #WebDevelopment #ProgrammingTutorial #KataSolution