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Prove: cos^6 θ- sin^6 θ= cos2θ(1- 1/4 sin^2 2θ)
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Prove: cos^6 θ- sin^6 θ= cos2θ(1- 1/4 sin^2 2θ)
Trigonometry: Multiple angles FOLLOW US:
Trigonometry: Multiple angles FOLLOW US:
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Prove: cos^6 θ- sin^6 θ= cos2θ(1- 1/4 sin^2 2θ)
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Prove: Cos^6 θ+ sin^6 θ= 1/4(1+3cos^2 2θ)
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Prove that sin^6θ + cos^6θ + 3sin^2θ cos^2θ = 1
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Prove: sin^6 A+cos^6 A=1-3sin^2 Acos^2 A
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`sin^(6) theta + cos^(6) theta ` is equal to
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show that sin ^6 theta + cos ^6 theta = -1/8 ( 5 + 3 cos 4 theta )/ easy solving / try hard
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The Maximum value of `cos^6 theta+ sin^6 theta` is :
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Expansion of cos 6(theta) # sin 5(theta)/sin (theta) # Trigonometry # Allied Maths -1
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sin^6(theta)+cos^6(theta) ,equal 1-3sin^2(theta).Cos^2(theta)@Mathby1069
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If `sin^(6)theta+cos^(6) theta-1= lambda sin^(2) theta cos^(2) theta`, find the value of `lambda`.
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Prove that sin^6 theta + cos^6 theta + 3 sin^2 theta cos^2 theta = 1 | Trigonometry class 10 extra
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2(sin^6 θ+cos^6 θ)-3(sin^4 θ+cos^4 θ)+1=0 @niharmhirani
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The value of the expression \[ \sin ^{6} \theta+\cos ^{6} \theta+3 \sin ^{2} \theta \cos ^{2} \t...
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Prove that : `sin^(6)A+cos^(6)A+3sin^(2)Acos^(2)A=1`
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#Trigonometric# most important question for see exam#prove that: sin^6A+cos^6A= 1/8(5+3 cos4A)
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RD Sharma Class 10 EX 11.1 Q 49: If sin theta+cos theta=x prove sin^6 theta+cos^6 theta=4-3(x^2-1)^2
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Trigonometry | 2(sin^6 θ+cos^6 θ)−3(sin^4 θ+cos^4 θ) = - 1
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