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Prove: sin^6 A+cos^6 A=1-3sin^2 Acos^2 A
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Prove: sin^6 A+cos^6 A=1-3sin^2 Acos^2 A
Prove: sin^6 A+cos^6 A=1-3sin^2 Acos^2 A
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`sin^6A+cos^6A=1-3sin^2Acos^2A`
Trigonometry
#Trigonometric# most important question for see exam#prove that: sin^6A+cos^6A= 1/8(5+3 cos4A)
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