If Tan A + B = Root 3 and Tan A - B = 1/Root 3. Find A and B values

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Sir which book question is this? Plzz tell me

narayanjee

Keep all exercise problem from chapter 8and 9

banukasupritha

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gamervictor

Sir how do learn trigonometry table I well forget again and again please tell me how do learn trigonometry table

fahimahmad

sir trikonamiti yKo nahin kataya jata hai

shatrudhansingh

2tanA=3 then find the value of (1+tanA) * (1-tanA)

s.shanmukha

Super sir now i understood very well thank you

Marwannot

Thanks for it my problem get solved by this video

nehasingh

@Math Army it didn't mention anything about the domain, which means that it wants all of the answers listed because trig. functions are periodic and has infinite answers. From there, if we take arctan on both sides of the equations and the other one also, that makes it arctan(√(3)) and arctan(1/√(3)). The answer must be π/3 for arctan(√(3)) and π/6 for arctan(1/√(3)) (in radians) (for degrees that is 60° and 30°). Because tan is positive in quadrants I and III, we add π to these angles, which is 4π/3 and 7π/6. Since it's periodic, there are infinite answers, and the formula must come up. In a simpler way, that would be π/3+nπ and π/6+kπ where n and k is an integer. We have to assume that n=k. Therefore, we set the system of equation as A+B=π/3+nπ and A-B=π/6+nπ. By the addition method, we can set 2A=π/2+2nπ, so A=π/4+nπ where n is an integer and B must be π/12. Otherwise, if you want to mention it in degrees, that would be A=(45+180n)° where n is an integer and B=15°

justabunga

Agar tan A _tanB na hokar multiply me ho

shivamtyagi

Sir samjati to acha ho lakin aabaj sudharo ni ko kuv video nii dhaka

atulthakur-tdhb

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