You are lowering two boxes, one on top of the other, down a ramp by pulling on a rope - Problem 5.33

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You are lowering two boxes, one on top of the other, down a ramp by pulling on a rope parallel to the surface of the ramp (Fig. E5.33). Both boxes move together at a constant speed of 15.0 cm/s. The coefficient of kinetic friction between the ramp and the lower box is 0.444, and the coefficient of static friction between the two boxes is 0.800. (a) What force do you need to exert to accomplish this? (b) What are the magnitude and direction of the friction force on the upper box?
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Why is the applied force not acting on the upper box

komikonupe
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would the answer to part a still be the same if the velocity was 300cm/s instead of 15? since the velocity was not like incorporated into the equations? also would the answer remain the same if question asked if the box was pulled up with a velocity of 15cm/s instead of pulled down?

pigdissection
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where did the normal force of the top block pushing on the bottom block go?

Sam-ilsq
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Sir, this question is from which book ?
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abhiseksingh
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for part a why don't we consider the second frictional force too?

astrar
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Why do we add Force applied to Force of kinetic friction?

beginnerbaroque