The Derivative of Parametric Equations

This video explains how to determine the derivative of equations in parametric form and how to determine the equation of a tangent line to a curve written as parametric equations.

[IvanBabravitski]

4:15 Reference triangle is supposed to be on the vertically mirrored side, to be more accurate but I've seen teachers before use that side as well to mean the same thing so it's probably still ok.

[canelaalcaraz]

I really appreciate all of your videos:)

[JohannesSchmitz]

In the first example, considering the plot at 2:40, what happens at x = 0 when your m goes to infinity? I am wondering if it is not better to deal with through deriving also a parametric equation for the tangent line which does not have this issue?

[johnjernigan]

"pi over 4 would be an angle in a 45 - 45 - 90 right triangle" No wonder students are confused. pi/4 is a number. It would also represent an angle in a pi/4 - pi/4 - pi/2 right triangle. There is no need to mentally switch from numbers (or angles measured in radians) to angles measured in degrees and then back.

[canelaalcaraz]

I may be wrong, but I am getting y = x - sqrt2. I’m thinking there may have been a mistake when cubing the last part of the problem?? Hopefully someone will see this one day and reply lol

[ssattor]

It be good if you could explain in your videos how the formulas that you use are derived. Mindless technique is just an extension of the concepts.

[bulldawg]

You're not alone: None of the videos on this topic provide any insight into the derivation of the central formula ... Saying to divide dy/dx by dt top and bottom isn't 'rigorous' enough for me ... But your effort in making these videos is appreciated :)