Second Derivatives of Parametric Equations With Concavity

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This calculus 2 video tutorial explains how to find the second derivative of a parametric curve to determine the intervals where the parametric function is concave upward or concave downward.

Derivatives of Parametric Functions:

Tangent Lines of Parametric Curves:

2nd Derivative - Parametric Equations:

3rd Derivative of Parametric Curves:

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Horizontal & Vertical Tangent Lines:

Area of Parametric Curves:

Arc Length of Parametric Curves:

Surface Area of Parametric Curves:

Polar Coordinates - Introduction:

Tangent Line Equations - Polar Form:

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Horizontal & Vertical Tangents - Polar:

Area of Polar Curves:

Area Between Polar Curves:

Arc Length of Polar Curves:

Surface Area of Polar Curves:

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Final Exams and Video Playlists:

Full-Length Videos and Worksheets:
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Your explanations are amazing and the reason I have a 92 in calc 2, 14 years after taking calc 1....you are my lifesaver!

deliap.
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This channel literally proves we literally attend lectures only to return home and learn via YouTube. 🤣Great video

Benedict_Miriti
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You're literally my Math units saviour. Keep uploading more videos. Huge help to lots of University students

Benedict_Miriti
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You explained this better than my teacher!!
Sir I hope you are doing amazing in life.

cinderellahour
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Professor Organic Chemistry Tutor, thank you for analyzing the Second Derivatives of Parametric Equations that Concaves Up or Down in Calculus I/II. This is an error free video/lecture on YouTube TV with the Organic Chemistry Tutor.

georgesadler
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Love from Africa! made 4.74 out of a 5.0 grade point all thanks to u ma man!
.

kamaldeenahmed
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Thank you, your videos are a great deal of help!

YuriDob
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u gotta do like a meet and greet session cuz ure so cool thank u sm!!!

marsyaalea
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"for the sake of practice, let's work on another one" JG always giving us the most practice for the best results

gatoradedickbackpack
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Another Superb Learning Session: ) Keep it up

mumtazhamid
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Can I know whether to include the (5/3)^(1/3) in the interval or not?

randomperson-fedf
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what if i first elliminate the parameter, will i get the same answer

ritakafulamwamba
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hello, how did you solve for "t" in the beginning to get 2?

dianaxestrada
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one error, once you have taken the second derivative with respect to t, which equaled 1/8, that means the entire graph respect to t is increasing, not only at point t=2.

jacksontet
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Why don't we derivative the dy/dx to get the second derivative? I got a different result if I do this. What's wrong here??? Thank you!

yiminzeng
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İ love you <3 thanks. From Turkeyy <3 :D

jopluayi
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What if d^2y/dx^2 does not include a t?

Orenjoos