Derivatives of Rational Functions

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This calculus video tutorial explains how to find the derivative of rational functions. It explains how to use the power rule, chain rule, and quotient rule in order to find the derivative of a fraction.

Equation of the Tangent Line:

Derivatives - Horizontal Tangent Line:

The Equation of The Normal Line:

The Equation of The Secant Line:

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Average and Instantaneous Velocity:

Instantaneous Rate of Change:

Derivatives of Rational Functions:

Derivatives of Radical Functions:

Derivatives of Fractions:

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Derivatives - Higher Order:

Simplifying Derivatives:

Derivatives - The Product Rule:

Derivatives - The Quotient Rule:

Derivatives - The Chain Rule:

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Final Exams and Video Playlists:

Full-Length Videos and Worksheets:

Derivatives - Formula Sheet:
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One day I will thank you for my degree, right now I just wanna thank you for the credits I have accomplished. Sometimes I wish I could actually see you, I hope you don't stop doing this for us, I can't believe that you do it for free. I could literally skip college and watch your videos, let us know of any other project you do, would love to share them with the world. I love your voice by the way.

thobilesikakane
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Professor Organic Chemistry Tutor, thank you for a basic explanation of the Derivative of Rational Functions in Calculus One. I also want to thank the viewers for finding the error in this video at the 4:00 mark.

georgesadler
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youre the goat. you get straight to the point with this stuff and make it so much less confusing

baileymerschman
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There's an error for the derivative of 9/x^2-6....It should be -18x/(x^2-6)^2

joshc
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Bro this taught me more in two minutes than my teacher has in 2 weeks

freshinfo
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I do really understand your explanation more than my proffesor. Sometimes during my maths class, I don't understand the maths explanation but upon watching those tutorials, I know much better and learn alot here. Thanks alot😘

mirrytahy
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Shortcut for derivative of a function of type: f(x) raised to g(x)
Let f(x) be f
Let g(x) be g
Let derivative of f(x) be f'
Let derivative of g(x) be g'
d/dx(f^g)=(f^g)(f'(g/f)+g' log(f))

For those who couldn't understand what's written above, It reads as:
derivative of f raised to power g is equal to f raised to power g times (derivative of f times g by f + derivative of g into log(f))

dong-wooklee
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Thanks A Lot
Was Searching For How To Differentiate Rational Functions
And Understood In 2 Min
And Its Cleared My 1 Week Doubt in 2 min
Thanks A Lot
Keep Uploading These Types Of Vedioes🙂👍

shashankshekhargupta
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Thanks bro your dedication to maths gives as an unbelievable help!

giannistsagarakis
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5 minutes in and I understand rational functions. Amazing

drewQ
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u saving so many lives bruh with yo crazy ass knowledge

anonymousmember
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Tutor how helpful and understandable your execution and clear the visuals, the monument of speech and concise problems prove satisfaction in my studies gd bls

alexeiaave
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Thank you So much for posting this, you are the reason I was able to understand and finish my homework tonight. You are amazing. Thank you again.

brettlandcoolidge
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Thank you so much. You teach and explain in a way that is easy and fast to understand. Keep it up. 🇷🇺learning from Russia 🇷🇺

tonderaibangwayo
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You're the best tutor that ever existed on 🌍

firelyrics
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How do you know all of this! You sound young!? Props to you

madinaroshan
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This guy can solo any math concept in mathverse

Freefranze
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I think you dropped x of -18 at 4:03!? It was supposed to be -18x/(x^2-6)^2 to my understanding!

nasserrahimi
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4:34 Can I use qoutient rule to this? Because why he rewrited it? What's the matter?

mfsusrides
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At 4:03, shouldn't the answer be -18x/(x^2-6)^2? He even said it was supposed to be -18x but I guess he forgot to write the correct answer

annikaj