AQA Core 3 Jan 2013 Q8

AQA Core 3 January 2013 question on integration by substitution involving exponential and trigonometric functions.

[mathedup]

You're are absolutely right. I went over this with a student and they said that they preferred the substitution way as they wouldn't have spotted the simplifying which is why I chose to do it that way in the video.. Maybe I should have mentioned both methods.. Good luck for tomorrow!

[goldfalls]

thanks man, the core 3 exam went really well! thanks to your help I'm sure. there was one 4 mark question I got wrong which was integrate (lnx)^2... which I know how to do so a bit annoying, I just made a small mistake and realised when I was checking through at the end!

[mathedup]

Don't worry about the 4 you didn't get and concentrate on the potential 71 you did get! It sounds like it went well so congrats!

[goldfalls]

this should be Jan 2013, not Jan 2012 in the title! thanks for the videos, so useful!

[qwobify]

Thank you! excellent video by the way, I wouldn't have found the January 2013 otherwise. :-)

[qwobify]

You complicated 8a so much. You can simply manipulate e^(1-2x) to equal e.e^-2x, and take e out the integral as a constant and then integrate e^-2x.

[mathedup]

Hi. I'm glad you are finding the videos useful. There are some D2 tutorial videos available through my website MathedUp! If you can contact through there, I can send you on a few extra bits that may help with your D2 revision..

[mathedup]

Hi. Try KS5>Applied maths>Decision 2

There are some bits under some of the sections there. I have posted a playlist for the Jan 13 exam paper (not by me) under "General resources".
For the other stuff, contact me through the website as I can't post links from here..

[mathedup]

Well spotted! Fixed it now :) Glad you are finding the videos helpful. Don't forget to check out my website, MathedUp!

Good luck for tomorrow!

[manrajdhanda]

Hi, I searched for a video on this question looking to see why -20/21 Is not an answer,
Because at the end when you have the final expression which you substitute 1 and 0 into, surely each of the terms can be negative? For example 1^7/2 , the 1 is square rooted then put to the power of 7. When square rooted cant it be positive of negative 1? This would apply to the other term too, giving a total of -20/21