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Branch current analysis explained using a simple example (with numerical solution in MATLAB/Octave)

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In this recording of a live-streamed exercise we discussed the solution of Task 20 b) about network analysis using the branch current method from our exercise booklet.
Octave commands:
R_1=10
R_2=20
R_3=30
R_4=40
matrix=[1 0 1 0;1 -1 0 0;0 0 1 -1;R_1 R_2 -R_3 -R_4]
I_s5=5
I_s6=6
source_vector=[I_s6;I_s5;-I_s5;0]
current_vector=inv(matrix)*source_vector
voltage_vector=current_vector.*[R_1;R_2;R_3;R_4]
Print version:
Mobile Version:
Chapter marks:
00:00 Idea of branch current analysis
02:15 Set up KCLs
05:15 Set up KVLs
11:22 System of equations in matrix form
12:50 Solution in GNU Octave
15:47 Check the solution
18:16 Alternative KVLs
Octave commands:
R_1=10
R_2=20
R_3=30
R_4=40
matrix=[1 0 1 0;1 -1 0 0;0 0 1 -1;R_1 R_2 -R_3 -R_4]
I_s5=5
I_s6=6
source_vector=[I_s6;I_s5;-I_s5;0]
current_vector=inv(matrix)*source_vector
voltage_vector=current_vector.*[R_1;R_2;R_3;R_4]
Print version:
Mobile Version:
Chapter marks:
00:00 Idea of branch current analysis
02:15 Set up KCLs
05:15 Set up KVLs
11:22 System of equations in matrix form
12:50 Solution in GNU Octave
15:47 Check the solution
18:16 Alternative KVLs