India | Math Olympiad Trigonometry Problem | Find x

In this video, I'll be showing you step by step on how to solve this Olympiad Maths Trigonometric Problem using a simple trick.

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[prollysine]

In a first approximation,
if true 7^1+7^0=8, --> if (cosx)^2=1, then (sinx)^2=0, or, 7^0+7^1=8, if (cosx)^2=0, then (sinx)^2=1,
Calculated, / (cosx)^2 = 1-(sinx)^2, /
let u=7^(cosx)^2, u^2-8u+7=0, (u-1)(u-7)=0, u= 1, 7, case 1, 7^(cosx)^2=1, or, case 2, 7^(cosx)^2=7,
case 1, 7^(cosx)^2=1, (cosx)^2=log1/log7, (cosx)^2=0/log7, (cosx)^2=0,
case2, 7^(cosx)^2=7, (cosx)^2=log7/log7, (cosx)^2=1,

[Respect-bdff]

I don't want to be cocky but this peoblem us way too easy, for Olympiad