Solving Equations Involving Modular Arithmetic - a = b(mod c) | SHS 2 CORE MATH

In this video, we are going to look at the topic Modular Arithmetic.
We are going to solve Equations involving modulo arithmetic.
We will learn how to find the (mod x) and so on.
a = b(mod c)

Modular Arithmetic sometimes referred to as Modular Arithmetic / clock arithmetic is a system a arithmetic for integers, where numbers "wrap around" after they reach a certain value - the modulos.
The best way to introduce modular arithmetic is to consider the face of a 12-hour clock.
It is realized that the numbers go from 1,2,3,4,5,6,7,8,9,10,11,12.
Now lets assume that it is 8 o'clock now, what will be the time in 5 hours? = 1 o'clock
Again assume that it is 10 o'clock now, what will be the time in 4 hours? = 2 o'clock.

solve 26 = 2 (mod x)

[alinekeah]

I understand your work correctly. Good teaching.

[DekuBernice-wzrw]

It was very easy but at a point it was quite confusing but I got what I was in search of.

[GideonOgbuehi]

In question 4 y did u not use 87 which when added to three gives 90?

[fideliaologunleko]

Sir we can add 5 to 87 which gives us 90 and 90 is divisible by 5 but this is what happened when I did it.
5x=3 mod 29
5x=3+87(mod 29)
5x÷5=90÷5
x=45 mod 29
And since 45 is greater than 29 we then divide.45÷29=1 r 16.
Therefore x=16 mod 29
I am not sure sir please help me explain. Thank you sir.

[PMe-mytd]

Would be great if there was an example with large numbers e.g., 125452x - 4 = 4 mod 15044

[vivianakoley]

Adding 3 to 87= 90 which is divisible by 5.

[AlhajiAjalloh-jp]

I want to offer five subjects like, further math, physics, chemistry and biology