Stable and Unstable Systems

Signal and System: Stable and Unstable Systems
Topics Discussed:
1. Bounded input and bounded output (BIBO) criteria.
2. Bounded signals.
3. Stable system.
4. Unstable system.
5. Examples of a stable system.
6. Examples of an unstable system.
7. Homework problem based on the stability of systems.

Music:
Axol x Alex Skrindo - You [NCS Release]

#SignalAndSystemByNeso #Signal&System #StableSystem #UnstableSystem #BIBO

[lovelykumari]

No need of ofline teachers... Your video is enough... Thanks on behalf of all electronics student..

[buqetmuolli]

The system in the homework problem is stable. If we take u(t) as the input and take into consideration that sin(t) is a bounded signal (it takes values from -1 to +1), then after multiplying these signals we get an output that is 0 from -infinity to 0 and from 0 to infinity looks like a normal sine function. So, the output of the system is bounded if the input is bounded.

[vladsamonin]

It's stable because amplitude of sin(t) is from -1 to 1 and you can do check for bounded input x=2 for example => sin(2)*x(2) is finite.

[rishitsharma]

Love the teaching style and how concise and yet precise everything is. I was pretty confused with this when my college professors taught this. But now its crystal clear and that too within minutes. Thanks a lot for these wonderful videos.

[muhammadwaqas]

stable system because the range of sin(t) is from -1 to +1

[ehsanabbasi]

that is a Stable system because Sin(t) is an Stable System :-)

[kavintong]

This is how teaching should be to the point precise at the same time easy to understand

[_shraddhakotrange]

I just like the way you write and the different color's you used.teaching...no words

[simonbenjamin]

Your lectures are brief and on point. They are helping me alot with my studies. #Zambia

[joshs.]

You can't prove a system stable by example. If you do that then you have to show that every bounded input results in a bounded output. You can only show that a system is not stable by example .

[smritismriti]

Thank u so much sir. Couldn't express my gratitude for this❤❤❤

[arpitmishra]

please make playlist on electrical machines also

[joeyzhou]

It is stable since sin(t) has value between -1 and 1, therefore by feeding any value to x(t), the output will always be finite.

[burgerking]

Wow! Thank you for the explanation! Amazing.

[akshaysingh]

if we take x(t) = sint (test signal) then it becomes y(t)=sin^2 t hence lies -1 <= sin^2 t<=1that is bounded .Hence it is stable. (symbol ^ : shows power).

[Mansoor.BSCEF]

stable system because the value the sint is bounded (-1 to 1)
Thanks for your great explanation

[afaqahmad]

it is bounded, cuz sin is bounded b/w -1 and 1, and any applied bounded I/P x(t) will just get multiplied to this limit, thus giving us finite output

[rajankarn]

a kind request.
please make a video on digital counters states counting problem.

[krismemolah]

Let the input be a dc of a value 4. After passing it through the system, we obtain the output to be 4sin(t) which is bounded from amplitude -4 to 4 in the interval -infinity to positive infinity and is therefore BIBO stable.

[mariama]

Great explanation by great teacher thanks a lot