The Riemann Function

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  1. Denis Potapov
  2. Riemann function
  3. Riemann integral
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I see a potential problem with your Lemma at 4:30. Suppose B=1/4. Then when x=2/3, f(x)=1/3 > B. Now let's look at your definition of all possibilities for x. s=[1/B] = [4] = 4. This means that x={1/4, 2/4, 3/4, 4/4}. Now notice that it's impossible to write down 2/3 (our original x) an k/4 where k is an integer. Therefore x=2/3 is not in this set, but it should be since f(x)>B. This is a contradiction. Am I missing something?

thekolbaska