How to find Support reaction for Beam || Only in 2 steps

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This video shows how to find the support reaction for a simply supported beam with uniformly distributed load and single pointed load. We can use three equilibrium equations to find the support reaction for any beam. In this lecture we will also show that how to verify the support reaction that either we calculate our support reaction correctly or not. For more details please watch full video.

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Beam support reaction
Beam reactions
beam analysis
beam design
Beam reactions design
simply supported beam
Beam with uniformly distributed load
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dude I never checked our module for this lesson, didn't know I'm gonna learn the entire thing under 10 mins 2 hrs before my exam, thank you so much

anotherpotatogamer
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I'm working as a highway engineer for 7 years I never used this formulas what I studied in college but I know the whole concept

bharathrambabu
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I have a test tomorrow and you just saved me. Thank you.

tylerunderwood
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you made it a whole lot easier. thank you, keep making vids!

Takoyaki-me
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I have a test in this afternoon, and because family problem I couldn't attend the previous class so you are truly my savior

anhkhoi
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What value come, if we taking moments at right hand side?

SSR-Vlogs
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I have a test tomorrow and you just saved me. Thank you. Thank you. Thank you. Thank you. Thank you. Thank you. Thank you. Thank you. Thank you. Thank you.Thank you.

MTJ
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hi thanks for great videos, please create a video and explain whats moment as im really confused whats it and why calculate it

sonofsun
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you are best teacher for student Tq sir

rituthakur
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Why there is no horizontal reaction at pinned support only vertical reaction?? Pinned support have 2 reaction right and roller has 1 that what I understood

faridsyahmi
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I think something is wrong...isn't it that you are supposed to ad that 2 that found as half of distance were udl lies to the other two distances 3 and 3

lushomomwiya
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would would the approach be if I had to solve for 2 more reactions? For example, what if there was a C on the 5KN and a D at the start of the distributed load?

debooty