Chapter 5 : Exercise 4 : Python tutorial 101

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This is exercise 4 of chapter 5

[yu_a_vi]

def filter(x):
fil = [[], []]
for i in x :
if i % 2 == 0:
fil[0].append(i)
else:
fil[1].append(i)
return fil
x = [1, 3, 4, 6, 7, 9, 13, 34, 56, 79]
print(filter(x))

[siddharthmalviya]

def seperate_odd_even(n: list)-> list:
"""This function takes a list as an arguments and returns odd and even number sepearated"""
return [[i for i in n if i%2 != 0], [i for i in n if i%2 == 0]]

[rangesh]

Well, this is my logic but I want to do it with pop and append method can anyone help me ???

def find(l):
length=len(l)-1
even=[]
odd=[]
for i in range(0, length):
if int(l[i])%2==0:
even.append(l[i])
else:
odd.append(l[i])
print(f"Even List: {even}")
print(f"Odd List :{odd}")

numbers=list(range(1, 11))
print(f"Entered List:{numbers}")
find(numbers)