Calculating the Escape Velocity on the Surface of the Earth

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In this video, I explain how to calculate the minimum velocity to escape earth's gravitational pull. I also explain why gravitational potential energy is written with a negative.

The escape velocity is the speed which we would have to shoot something vertically up to completely remove it from Earth's gravitational pull.

What you'll need:

Kinetic Energy: (KE=1/( 2 ) mv^2 )
Gravitational Force: (F=G (m_1 m_2)/r^2 )
Gravitational Potential Energy : (G_PE=−G (m_1 m_2)/r)
Gravitational Constant: (G=6.7×〖10〗^(−11) N⋅m^2/(kg^2 ))

[CyprianKazmierczakPiano]

Hi, I know im kinda late but the radius in the denominator should be squared

[aydinozdemir]

How much fuel or energy does it need for that object to escape

[aydinozdemir]

Here you considered that object as a one shot bullet right? Because if a rocket goes vertically with speed of 100 m/s, it will eventually leave earth, right?

[paniniman]

may I know where you downloaded that calculator?

[swedensy]

This is actually very bad explanation, cause i could have a stairs or space elevator with heights 300km, i could just climb with 0.5m per seconds and reach the top.