A2 U5.13

[Michael.Pineda]

Michael. P. 4
To find when it would reach 111°F I used the same formula for the previous question, but this time I replaced 45 with 7.25. So my final equation was -25(1/e)^.08*7.25+125

[Ace-qlyc]

Angel Carrillo Per 4
1) log (100, b)=144
2.) Do we use Newton law in future examples/ problems. Is it important to remember this law.

[christiancervantes]

Christian Cervantes P.1
It will take approx 50 min for the water to be at 111 and i calculated using the equation

[michaelromero]

Michael Romero Period 2 
For  the last problem what equation do we use to solve it. After solving the equation the water will be at 111 F in about 45 mins

[raullopez]

Raul L.
Period 2

For the last problem, to set up the equation will the interstate be subtracting?

[bv]

Brandon.BV.Period 2
My question is what kinda of formula would we do for the tub problem, I was a bit stuck.

[yancyflorence]

yancy F.
My question is about the tub problem and when we rewrite newton's problem are we just plugging in the values for the initial problem into newtons equation?

[hectorcabrales]

Hector.C.Period 4
For the water tub questions, the ^08t confused me only because the word problem didn't have that. Is it the e value that makes that happen?

[Deadmanwalkshere]

Johan M. P.2
For the Tub problem would we have to divide the 45 to the final result or do we just plug in the equation to wolfgram alpha? Would the equation work if we plug in 111?

[jacoblarue]

Jacob larue
What formula do we use for the third problem

[jonathanmarcelino]

I get confused on whether we should should convert the b^(-s*t) to (1/b)^(s*t)
I know that they have the same answer but 
I want to know the circumstance for me to do the conversion.

[sjplaysgames]

For the angel problem how would you set up the problem

[chxngeless]

My question is if the room temperature is below the starting temperature and our starting temperature is steadily decreasing how will it not meet that temperature?

[robertomiranda]

Roberto M. period 4
For the problem I would get 46 minutes when put into the Newtons law

[albertoromero]

Alberto R. Per.1
The water will be at 111° F at around 50min.

[chxngeless]

100e (-.08t) +125= 111 was my equation

[brianflores]

Brian F. Per.4
I got (log base e of .56)/-.08=t.
You said we were supposed to plug in 45 for t in the tub problem. I instead set the equation equal to 45, is that alright?

[tamirmartin]

Tamir Martin
I was entire tub problem

[JoseAlonso-kuom]

Would 1/e be divided on both sides of the equal sign for the first problem

[timmothyroberts]

Timmothy Roberts per 1
I need help putting this equation in my calculator but my equation is
° T(t)=-25(1/e)^.08+111