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Using the properties of determinant prove|α β γ||α² β² γ²||β+γ γ+α α+β|=(α–β)(β-γ)(γ-α)(α+β+γ)
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Using the properties of determinants, prove that
|α β γ|
| α² β² γ²| =(α – β)(β-γ)(γ-α)(α+β+γ)
|β +γ γ +α α+ β|
|α β γ|
| α² β² γ²| =(α – β)(β-γ)(γ-α)(α+β+γ)
|β +γ γ +α α+ β|
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