Solving Factorable Polynomial Inequalities Algebraically Part 1

This lesson shows how to solve linear inequalities and some factorable polynomial inequalities algebraically. This is the first part of a two part lesson. This lesson was created for the MHF4U Advanced Functions course in the province of Ontario, Canada.

[boredom]

You are my new favorite person on the internet.
Thank you.

[Balrenn]

Your vids are definitely the most informative and easy to follow. Great job.

[xmrgenox]

thank you so much for this video!i was doomed for a quiz tomorrow over this, until i saw this video! thanks so much! ur the answer to my prayers

[chima]

thank you so much, u helped me pass my math test :D

[myfathersangels]

oh my gosh this helped me much. i take an online algebra 2 class and i cold not figure this out! thank god for youtube

[AlRichards]

@craxtion4 Not just cubic polynomial inequalities have infintely many solutions. Think of the inequality x^2 > 4. Any number larger than 2 or less than -2 is a solution. So on the number line any number left of -2 or right (above) +2 is a solution. Thus there's an infinite number of solutions to most inequalities.

[BigBodyPresence]

thanks for the help my teacher couldn't even explain this to me!!

[AlRichards]

@yomaster29 This is an algebriac method (notice the factoring and isloating for x) with a case table. There may be other "algebraic methods" - this one doesn't have to be the only one.

[Kar]

Sir keep up the good work, I'm loving it!

[RedVelvetScorpio]

Thank you so much! I missed this lesson due to being sick and my teacher barely explained it to me. Now I think I understand. :)

[AlRichards]

@baluwatar414 How could you tell? :) yes, I certainly am Canadian.

[craxtion]

can you briefly explain why cubic polynomial inequalities have infinitely many solutions

thanks

[baluwatar]

@AlRichards314 the way you were pronouncing "about"...

[khashya]

@AlRichards314 ..for 3:11 why cant you just put "x < -4" why do you have to switch the sign