Using chain rule twice to take the derivative of an expression

👉 Learn how to find the derivative of a function using the chain rule. The derivative of a function, y = f(x), is the measure of the rate of change of the function, y, with respect to the variable x. The process of finding the derivative of a function is called differentiation. There are various methods of finding the derivative of a function including, direct differentiation, product rule, quotient rule, chain rule (function of a function), etc.
When given a function of the form y = f(g(x)), then the derivative of the function is given by y' = f'(g(x))g'(x). This method of differentiation is called the chain rule. The chain rule is used to find the derivative of a function that is a function of another function.

Organized Videos:
✅The Derivative
✅Find the First and Second Derivatives of a Function
✅Find the Differentiability of a Function
✅Find the Derivative of Absolute Value Function
✅Find the Derivative of Exponential and Logarithmic Functions
✅Find the Derivative using Implicit Differentiation
✅Find the Derivative of Inverse Functions
✅Find the Point Where the Tagent Line is Horizontal
✅Write the Equation of the Tangent Line
✅Find the Derivative from a Table
✅Chain Rule Differentiation
✅Product Rule Derivatives
✅Find the Derivative of Trigonometric Functions
✅Find the Derivative using the Power Rule
✅Quotient Rule Derivatives
✅Solve Related Rates Problems

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[aaliyahvarona]

Thank you so, so much for this. I was stuck on a double chain rule problem my instructor gave me. He only gave us one problem, and it went by really quick I barely started processing and understanding when he finished. You are a life saver! Appreciate it.

[hamzakhalid]

Thanks man always coming through clutch

[Configu]

ain’t it a triple chain rule since we have 4, sin(g(x)), g(x)

[mustafamalik]

Could you explain why f(x) = x^4? I thought it would be sin^4(x)

[davidwestbrook]

if the chain rule is f'(g)*g'....I thought a three part chain rule, like this problem, was f'(g)*g'(h)*h'