Derivative of Inverse Hyperbolic Trigonometry: sech^-1(x)

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In this video I go over the derivative of inverse hyperbolic secant or sech^-1(x) and show that it is equal to -1/(x·sqrt(1-x^2)).

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I don't always solve derivatives of inverse hyperbolic trig but when I do I need to know the domain first ;)

mes
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very clear. thank you for sharing such a nice solution

linjingxuan