Finding Distance from a Point to a Line

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Learn how to find the distance from a point to a line in this free math video tutorial by Mario's Math Tutoring.

0:10 Finding the Distance From (1,5) to y=2x+5
0:53 Finding the Slope of the Perpendicular Line
1:00 Using Point Slope Form of the Line
2:03 Using the Substitution Method to Find the Point of Intersection
2:54 Using the Distance Formula Between the 2 Points

Related Videos:

Formula For Finding the Distance From a Point to a Line

Finding Equation of Perpendicular Bisector

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Your lessons are truly amazing. My teacher took 34 minutes explaining this and I was left confused, but you took 3 minutes and 34 seconds and taught me more than her. Pretty cool mate!

ishanbhansali

Excellent work agent 47. Now make your way to the extraction point.

victorkotov

That was plain and simple and straight to the point. Well done good sir. :)

wardenofthelight

thank you, my teacher had a hard time explaining how to do this

alaynac

I have a test today and I almost forgot about this, thank you so much 😀

koolaiddudeawesome

I just used this method to find the nearest distance between a curve and a line!

adityaadit

Absolute lifesaver, thank you very much!

PraPal-ue

Revisit this problem after learning rotations in geometry, vectors in precalculus and optimization in calculus

alfonsorodriguez

Anna Pitts,

When dealing with square roots, you always try to simplify the number WITHIN the square root sign to the simplest numbers, in order to factor out as many of them as you can, and something that is not easily divisible just leave inside the square root sign, as a whole number, (for the sake of neatness).
In the case of the number 20, inside the square root sign, we can break up the 20 into 4 • 5, (because you can separate the numbers within square root into separate square roots, if they are multiplied by one another, and cannot separate them if they are added, or subtracted from each other).
So, as we brake up sqrt(20) into sqrt(4) • sqrt(5), we can now have an easily squarerootable 4, which is 2^2, and not easily squarerootable 5, which we leave as it is. And thus, we can simplify the whole expression as follows:

sqrt(20) = sqrt(4 • 5) = sqrt(4) • sqrt(5) = 2 • sqrt(5) = 2sqrt(5)

which is what he did...

If it was, say, sqrt(45), we could do the same:

45 can be broken down into 9 • 5, where 9 is easily squarerootable down to 3. So, we get,

sqrt(45) = sqrt(9 • 5) = sqrt(9) • sqrt(5) = 3 • sqrt(5) = 3sqrt(5)

That's how we deal with large messy square roots.

JohnSmith-oksn

Impeccable Video! Thank you for you tutorials.

pokohoko

Thank you, this one of the best explanations ever!!!!

AdityaGupta

bruh my teacher took 3 and a half total hours to explain this completely and you did it better in under 4 minutes

spektyr

Parents: YOUTUBE ROTS YOUR BRAIN!!!

Also Youtube: Literally helps me find what Im doing wrong and quite possibly saves my tomorrow’s test grade

Thank you man, this is a lifesaver

BaldSteveGaming