Distance Between Point and Plane - Example 1

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An example working through how to compute the distance between a point and a plane.

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Thanks for the great explanation and easy to understand steps!

PLP
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Hi Clary, no it is correct. The formula for a plane is a(x-x0) + b(y-y0) + c(z-z0) = 0. So with the first term 4(x+2), the a=4 and the x0 = -2 since it has x+2 which equals x - (-2). Hope that helps. :)

fireflylectures
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Brief and useful, i really enjoyed it.
🙂🙏

visas
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From where does uh get value of 'P' and normal 'n' ??...plz clear my doubt

hafsaimtiaz
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how do you decompose the plane formula in standard form to your point "p" and and the normal vector "n"?

CocoaThunda
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Hi great video! But Is P meant to be (2, -5, 0) instead of negative 2?

dreamurlife
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Please could you explain how you get P = (-2, -5, 0) . thanks.

garethm
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How do you find the distance if only a point Q and the Cartesian equation of the plane are given? I just subbed in random values into the equation to find a point P, but I can only find the magnitude of vector PQ and have no other information, no way of finding a point N or vector n

crochetyoustay
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Shouldn't we get the magnitude of the dot product (5)?

fabiannghitewapo
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Way easier to just sub coordinates of point P(x1, y1, z1) into cartesian equation / n of cartesian equation.

|Ax1+By1+Cz1+D|
d=
√(A^2 +B^2+C^2)

brcarter