In a charming 19th-century hotel, an old-style elevator is connected to (READ DESC) - Problem 9.18

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I didn’t read carefully enough and thought the diameter was radius. Feel free to follow my steps but use 1.25 as the radius!!!

9.18 • In a charming 19th-century hotel, an old-style elevator is connected to a counterweight by a cable that passes over a rotating disk 2.50 m in diameter (Fig. E9.18). The elevator is raised and lowered by turning the disk, and the cable does not slip on the rim of the disk but turns with it. (a) At how many rpm must the disk turn to raise the elevator at 25.0 cm/s? (b) To start the elevator moving, it must be accelerated at 18g. What must be the angular acceleration of the disk, in rad/s2? (c) Through what angle (in radians and degrees) has the disk turned when it has raised the elevator 3.25 m between floors?
University Physics with Modern Physics
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be careful, part b is asking for 1/8(9.81) divided by the radius, not diameter. so instead of divided by 2.5 it would b 1.25

NotRealLifeBrand
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can we use diameter to solve this question...? I thought we had to use the radius so I divided the diameter into half to solve this question.

juyeonkang
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Didnt you calculate just tangental acceleration? Shouldnt we calculate both radial and tangental, and then from them find the linear acceleration?

SeyranTaganov