Derivative of inverse cosine | Taking derivatives | Differential Calculus | Khan Academy

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Differential calculus on Khan Academy: Limit introduction, squeeze theorem, and epsilon-delta definition of limits.

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As always, Khan Academy has the go-to video for understanding.

cepson
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So d/dx of cos^-1(x)+sin^-1(x) is equal to zero!

AMalas
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Bless your soul. I’ve been trying to find this prove

anaonofre
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Would you start writing big words I love your works but I have problem with my eyes am finding difficulties in following.i will appreciate

mikelfrederick
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isn't sin(y) also equal to -sqrt(1-cos^2y)? Why did we pick the principal square root, being the negative a totally legit option?

michelef
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So that means arcsin(x) really is -arccos(x) or is -arccos(x) + some constant?

helloitsme
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why can't you just use chain rule? I don't understand

xanh