R3.2.9 Describe, using equations, the oxidation reactions of alcohols [SL IB Chemistry]

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This and the next video cover what you need to know but
a) warm acidified dichromate is the oxidizing agent [Cr6+ (orange)  Cr3+ (green)]
b) distillation allows the collection of the aldehydes (normally this would continue to react to form a carboxylic acid)
c) reflux allows the production of the carboxylic acid
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Reflux it a bit and get the aldehyde mostly, reflux a bit more to get the carboxylic acid mostly. Distill of the aldehye to (it has the lowest boiling point).
Reflux is a technique (heat a container and the vapours go up a tube, condense and fall back down).

ibchemvids
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YOUR VEDIOS ARE VERY NICE THERE ARE MANY OF MY FRIENDS WHO STRUGGLE WITH CHEMISTRY I WILL RECOMMEND THIS CHANNEL

nithinalluri
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At 1:34, I didn't really understand what you meant by 'you can burn it'?

awesomesheen
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no because the chromium is changed at the end from Cr6+ to Cr3+. Catalysts remain unchanged at the end.

ibchemvids
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I don't understand the reflux part? is it just something that is used in the primary oxidation from the aldehyde to the carboxylic acid phase?

fanChelsea
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Is it correct to say that in the oxidation of primary alcohols K2Cr2O7 is a catalyst?

mmagdaPL
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ok, so K2Cr2O7 is just the oxidizing agent?

mmagdaPL
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lol laughed when he said disorder.... jokx

maannnyy
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but...traffic lights go from green to orange...
(good video though)

hrcu