Outsmart the Radical Equation Challenge: Can You Crack It?

preview_player
Показать описание
Hello My dear family I hope you all are well if you like this video about "Outsmart the Radical Equation Challenge: Can You Crack It?" for Math Olympiad Preparation then please do subscribe our channel for more mathematical challenges and Olympiad preparation tips.

Ready for a math challenge? Outsmart the Radical Equation Challenge and see if you can crack it! Dive into this tricky puzzle and put your algebra skills to the test. Perfect for math enthusiasts, students, and anyone looking to sharpen their problem-solving abilities. Can you find the solutions?

In this tutorial, you'll get:

A step-by-step walkthrough of the problem
Key strategies and techniques for solving radical equations
Tips to avoid common mistakes
Insight into advanced problem-solving methods

Think you have what it takes to solve this hard radical math problem? Watch the video, give it a try, and let us know your solution in the comments below.

#mathchallenge #radicalequations #mathpuzzles #algebra #problemsolving #mathskills #stem #mathenthusiasts #brainteasers #mathfun #learnmaths #education #challengeaccepted #mathproblems

Thanks for Watching!!

Do not forget to like, share and subscribe our channel for many more mathematical adventures.
@infyGyan
Рекомендации по теме
Комментарии
Автор

Cool, would be interesting to see how the irrational roots could be checked, is it possible?

lukaskamin
Автор

It was an informative and wonderful explanation. Thanks for sharing....finally x=-2

mohammedsaysrashid
Автор

After inferring that the equation is self-similar, it simplifies to

x = 2(1 + x)^⅓

Substituting y = x/2 and cubing

y³ = 1 + 2y
=> y³ - 2y - 1 = 0

Using RRT and SDM

(y + 1)(y²-y-1) = 0

Solving

y = -1, (1 ± √5)/2

Or

x = -2, 1 ± √5

dorkmania
Автор

Divide both sides by 2 we have x/2=cbrt(1+2*cbrt(x+1)). Cube both sides we now have (x/2)^3=1+2*cbrt(x+1). Add both side with x we have Let a=x/2, b=cbrt(x+1) and function f(t)=t^3+2t. The equation will turn into f(a)=f(b). Besides, notice that f(t) is increasing function on R (f'(t)=3t^2+2>0) so a=b or x/2=cbrt(x+1). Multiply both side by 2 and cube both side we have x^3-8x-8=0 <=> (x+2)(x^2-2x-4)=0

ducduypham
Автор

Cubing both sides,
and letting 8x +8 =y^3
results in a system of 2 cub eqns,
x^3 -8 = 8y ..(1)
y^3 -8 = 8x ..(2).
Sutracting
x^3 -y^3 +8(x -y) = 0;
(x -y)(x^2 +xy +y^2) +8(x-y) =0;
(x -y)(x^2 +xy +y^2 +8) =0;
that is,
x -y =0, i.e., x = y ..(3)
Substituting (3) into (1),
x^3 -8x -8 =0,
(x +2)(x^2 -2x -4) =0;
and thus
x = -2
x = [1 +&- sqrt(5)]/2

While
x^2 +xy +y^2 = -8;
4x^2 +4xy +4y^2 = -32;
(2x +1)^2 +3y^2 = -32,
+ve LHS = -ve RHS
yields cmplx sols.

woobjun
Автор

Could get the solution. Not so challenging

gnanadesikansenthilnathan