INJECTIVE, SURJECTIVE, and BIJECTIVE FUNCTIONS - DISCRETE MATHEMATICS

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We introduce the concept of injective functions, surjective functions, bijective functions, and inverse functions.

#DiscreteMath #Mathematics #Functions

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I've got to say, you are far better than the professor I have for Discrete Math, it has everything to be quite the interesting, but some people just cannot teach. Anyway, thanks for the videos

FMAPR
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Seriously... that's it?? Why was this to complicated when our professor taught it. Thank you so much!

SgtMajorJay
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Discrete Math is so fun, when i can understand it

Thank you Sir, for helping me pass my exams

BangMaster
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Injective: 0:39
Surjective: 5:25
Bijective: 10:07

TheMrsteakman
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You are by far the best teacher of Discrete Math compared to any other youtube tutors as well as my Uni teacher

michaelsun
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aidahuseynova
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speclesic
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RadRobbie
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mustafakhanani
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Panditatt
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icy
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ahmedbahaj
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lizziethelemon
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f: R->Z given by f(x)=5x+2 is NOT surjective. It's clear just from looking at it that the range of f(x) is R, but the codomain of the function is Z, so it is not surjective. If, on the other hand, you're talking about the function f:R->Z given by f(y)=(y-2)/5, this again is not surjective by the same reasoning. For either of these functions to be surjective, you'd need f:Z->R

jamesbaldwin
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I have watched most of your Discrete Math tutorials. They are easy to understand and well arranged. I like your tone of voice which in not monotonous for a tutor. So Thank you and I hope you would develop more contents in the other areas. you greatly helped me in my last DM test.

hessnej
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"x2 was just x1 in disguise". This sentence alone clarified everything to me. My private tutor couldn't explain it to me in an hour. I assumed that if we were to put different numbers like 1 and 2, the outcome will be different. so f(1) not equal to f(2). Now I understand that f(x2) can not be different, and that is essentially what we had to prove. Thank you very much.

mclovin
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amonGustavo