Sum of First N Cubes Equals Square of 1+2+3+...+n | Number Theory

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The sum 1^3 + 2^3 + 3^3 + ... + n^3 is equal to (1+2+...+n)^2. Amazing! In today's number theory video lesson, we'll prove this wonderful equality using - you guessed it - induction!

The sum of cubes and the sum of squares are cool, but the sum of cubes and the square of a sum is an even cooler pair!

I hope you find this video helpful, and be sure to ask any questions down in the comments!

+WRATH OF MATH+


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Beautiful, this proof will help me for my class, patterns for Dr. Gannons triangle: related to 1^3 + 2^3+3^3++++ = a perfect square value, thank you.

juanjaimescontreras
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Very well done! In your opinion, is this a "what a funny coincidence" kind theorem, or a "deep meanings are revealed" kind? It feels like the former to me, but it's still a nice example of how to do an induction proof.

mattkilgore
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The usage of the board is insane ! Congratulations

antoine
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Thank you soo much we just needed to used that formula n(n+1)/2

samiaakram
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Oh, I just needed to use this n(n+1)/2 formula while prooving... Thank you! :)

katiasavina
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did not know about this formula, my book formula looks different, this is much easier, thank you

aryamanjha
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If you're watching this reply me with your age

ayushjaiswal
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I got asked this in an interview question. I proved it by induction like you did but they asked for a geometric interpretation? Can anyone who has one reply to this comment?

finlayhutchinson