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`tan^(-1)((sqrt(1+x^(2))+sqrt(1-x^(2)))/(sqrt(1+x^(2))-sqrt(1-x^(2))))`
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`tan^(-1)((sqrt(1+x^(2))+sqrt(1-x^(2)))/(sqrt(1+x^(2))-sqrt(1-x^(2))))`
0:05:39
`tan^(-1)((sqrt(1+x^(2))+sqrt(1-x^(2)))/(sqrt(1+x^(2))-sqrt(1-x^(2))))`
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if `tan^-1 {(sqrt(1+x^2)-sqrt(1-x^2))/(sqrt(1+x^2)+sqrt(1-x^2))}=alpha` then `x^2` is:
![Prove that `tan^(-1)[(sqrt(1+x^2)+sqrt(1-x^2))/(sqrt(1+x^2)-sqrt(1-x^2))]=pi/4+1/2cos^(-1)x^2`](https://i.ytimg.com/vi/zQb6ieGikWk/hqdefault.jpg)
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Prove that `tan^(-1)[(sqrt(1+x^2)+sqrt(1-x^2))/(sqrt(1+x^2)-sqrt(1-x^2))]=pi/4+1/2cos^(-1)x^2`
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If `tan^(-1){(sqrt(1+x^2)-sqrt(1-x^2))/(sqrt(1+x^2)+sqrt(1-x^2))}=alpha,` then prove that `x^2=s...
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`y=tan^(-1)((sqrt(1+x^2)+sqrt(1-x^2))/(sqrt(1+x^2)-sqrt(1-x^2))),w h e r e` `-1 ltx lt1,x!=0`
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Integral of 1/sqrt(1-x^2)
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`tan^-1((sqrt(1+x^2)-1)/x)' | tan^(-1)(sqrt(1+x^(2))-1)/(x) x is not equal to 0
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Integral of 1/(x^2)sqrt(1-x^2) (substitution)
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integral of sqrt(1-x^2), trig substitution, calculus 2 tutorial
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hyperbolic substitution, integral of sqrt(1+x^2)
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integral of sqrt(1+x^2), trig substitution, calculus 2 tutorial
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When mathematicians get bored (ep1)
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Integral of x/sqrt(1-x^2)
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tan^(-1)((sqrt(1+x^(2))+sqrt(1-x^(2)))/(sqrt(1+x^(2))-sqrt(1-x^(2))))=pi/4+1/2cos^(-1)x^(2)`
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Prove that cos(sin^(-1)) = sqrt(1-x^2). Inverse Trig Functions
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Let me quickly integrate x/sqrt(1-x^2)
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Find derivative of g(x) = tan^(-1)(x - sqrt(1 + x^2)). Derivatives of Inverse Trig Functions
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integral of 1/(x^2*sqrt(x^2-1), trig substitution, calculus 2 tutorial.
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Differentiate `tan^(-1)((sqrt(1+x^(2))+1)/(x))` w.r.t. x.
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Integral of sqrt(x^2+1), integral of sqrt(x^2-1), integral of sqrt(1-x^2)
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Prove that derivative of sin^(-1) x = 1/(sqrt(1- x^2)). Derivatives of Inverse Trig Functions
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Differentiate `tan^(-1)sqrt((1-x^(2))/(1+x^(2)))` with respect to `cos^(-1)x^(2).`
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