1996 IMO Problem #2

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  1. Mr. Math
  2. 1996 IMO
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Really helps me practice for this years IMO. Great work!

caputlp
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I support this channel :) so sad that only few people are interested.

kennethshi
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Or u could use an inversion by the point A. Then the given condition converts to very clean equation: C’B’P’=B’C’P’

piotrek
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Or you can just rotate down ABP and ACP respectively to similar triangles with side BC and use similarity & congruence to prove.

cr
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